As for how the table would be used, my thinking is that the player would just make a 1d100 roll, where each row in the table would have 2 percentage points (i.e. the first row would be 01-02%, the second row would be 03-04%, and so on).
The remaining 2 (2% per row) or 4 rows (1% per row) would probably be for anomaly orbital sets. For example, perhaps one possibility might be an "orbital set" comprised of a single orbit, where the player rolls 1d100 and the result is the orbit in LM (1-100 LM). Another could be no orbits at all. Another could be for the player to roll again against the table (ignoring the anomaly orbits), but remove all the odd numbered orbits (or the even numbered orbits) from the row. Or maybe wipe out all orbits over 50 LM. There's room for some strangeness.
Anyways, comments, criticisms, flames? Fire away.

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M=2
1 3 5 9 17 33 65 129 257
1 4 7 13 25 49 97 193
1 5 9 17 33 65 129 257
1 6 11 21 41 81 161 321
2 4 6 10 18 34 66 130 258
2 5 8 14 26 50 98 194
2 6 10 18 34 66 130 258
2 7 12 22 42 82 162 322
3 5 7 11 19 35 67 131 259
3 6 9 15 27 51 99 195
3 7 11 19 35 67 131 259
3 8 13 23 43 83 163 323
4 6 8 12 20 36 68 132 260
4 7 10 16 28 52 100 196
4 8 12 20 36 68 132 260
4 9 14 24 44 84 164 324
M=2.25
1 3 6 11 24 52 116 260
1 4 8 16 35 78 174
1 5 10 21 47 104 232
1 6 12 26 58 129 289
2 4 7 12 25 53 117 261
2 5 9 17 36 79 175
2 6 11 22 48 105 233
2 7 13 27 59 130 290
3 5 8 13 26 54 118 262
3 6 10 18 37 80 176
3 7 12 23 49 106 234
3 8 14 28 60 131 291
4 6 9 14 27 55 119 263
4 7 11 19 38 81 177
4 8 13 24 50 107 235
4 9 15 29 61 132 292
M=2.5
1 3 6 14 32 79 196
1 4 9 20 48 118 294
1 5 11 26 64 157
1 6 14 32 79 196
2 4 7 15 33 80 197
2 5 10 21 49 119 295
2 6 12 27 65 158
2 7 15 33 80 197
3 5 8 16 34 81 198
3 6 11 22 50 120 296
3 7 13 28 66 159
3 8 16 34 81 198
4 6 9 17 35 82 199
4 7 12 23 51 121 297
4 8 14 29 67 160
4 9 17 35 82 199